二次方程式の解の公式の証明

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ax2 + bx + c = 0

x2 + b a x + c a = 0

x2 + b a x = - c a

x + b 2a 2 - b 2a 2 = - c a

x + b 2a 2 - b2 4a2 = - c a

x + b 2a 2 = + b2 4a2 - c a

x + b 2a 2 = + b2 4a2 - 4ac 4a2

x + b 2a 2 = b2 - 4ac 4a2

x + b 2a = ± b2 - 4ac 4a2

x + b 2a = ± b2 - 4ac 2a

x = - b 2a ± b2 - 4ac 2a

x = -b ± b2 - 4ac 2a